Class 12PhysicsElectromagnetic wavesMaxwell's equations , Concept of displacement current and Hertz experiment
EasyWrite the meaning of the equation $i = i_c + i_d$.
(N/A) The equation $i = i_c + i_d$ represents the total current in a circuit,which is the sum of the conduction current $(i_c)$ and the displacement current $(i_d)$.
$1$. Conduction current $(i_c)$: This is the current due to the actual flow of charges (electrons) through a conductor.
$2$. Displacement current $(i_d)$: This is the current that arises due to the time-varying electric field in a region,such as between the plates of a capacitor.
This equation was proposed by James Clerk Maxwell to generalize Ampere's Circuital Law,ensuring that the total current is continuous even in regions where there is no physical charge flow,such as across a capacitor gap.
$1$. Conduction current $(i_c)$: This is the current due to the actual flow of charges (electrons) through a conductor.
$2$. Displacement current $(i_d)$: This is the current that arises due to the time-varying electric field in a region,such as between the plates of a capacitor.
This equation was proposed by James Clerk Maxwell to generalize Ampere's Circuital Law,ensuring that the total current is continuous even in regions where there is no physical charge flow,such as across a capacitor gap.
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$A$ parallel plate capacitor is charged to $60\,\mu C$. Due to a radioactive source,the plate loses charge at the rate of $1.8 \times 10^{-8}\, C/s$. The magnitude of the displacement current is:
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View SolutionThe Hertz experiment is used for:
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View SolutionMatch List-$I$ with List-$II$ and choose the correct answer from the options given below:
| List-$I$ | List-$II$ |
| :--- | :--- |
| $A$. Gauss's law of magnetostatics | $I$. $\oint \vec{E} \cdot d\vec{a} = \frac{1}{\epsilon_0} \int \rho dV$ |
| $B$. Faraday's law of electromagnetic induction | $II$. $\oint \vec{B} \cdot d\vec{a} = 0$ |
| $C$. Ampere's law | $III$. $\oint \vec{E} \cdot d\vec{l} = -\frac{d}{dt} \int \vec{B} \cdot d\vec{a}$ |
| $D$. Gauss's law of electrostatics | $IV$. $\oint \vec{B} \cdot d\vec{l} = \mu_0 I$ |
| List-$I$ | List-$II$ |
| :--- | :--- |
| $A$. Gauss's law of magnetostatics | $I$. $\oint \vec{E} \cdot d\vec{a} = \frac{1}{\epsilon_0} \int \rho dV$ |
| $B$. Faraday's law of electromagnetic induction | $II$. $\oint \vec{B} \cdot d\vec{a} = 0$ |
| $C$. Ampere's law | $III$. $\oint \vec{E} \cdot d\vec{l} = -\frac{d}{dt} \int \vec{B} \cdot d\vec{a}$ |
| $D$. Gauss's law of electrostatics | $IV$. $\oint \vec{B} \cdot d\vec{l} = \mu_0 I$ |
DifficultJEE MAIN 2024
View Solution$A$ parallel-plate capacitor with circular plates is being discharged. The radius of the circular plates is $10 \ cm$. $A$ circular loop of radius $20 \ cm$ is concentric with the capacitor and located halfway between the plates. If the electric field between the plates is changing at the rate of $3.6 \times 10^{12} \ V/(m \cdot s)$,then the displacement current through the loop is (Assume $\frac{1}{4 \pi \varepsilon_0} = 9 \times 10^9 \ N \cdot m^2/C^2$) (in $A$)
$A$ time-varying potential difference is applied between the plates of a parallel plate capacitor of capacitance $2.5 \mu \text{F}$. The dielectric constant of the medium between the capacitor plates is $1$. It produces an instantaneous displacement current of $0.25 \text{ mA}$ in the intervening space between the capacitor plates. The magnitude of the rate of change of the potential difference will be . . . . . . $\text{V s}^{-1}$.
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